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A 0.91 kg ball and a 2 kg ball are connected by a 0.95 m long rigid, massless rod. The rod is rotating clockwise about its center of mass at 35 rpm. What torque will bring the balls to a halt in 10.44 s

2 Answers

5 votes

Final answer:

To bring the balls to a halt, calculate the torque required by finding the weight of the balls and multiplying it by the distance between them.

Step-by-step explanation:

To bring the balls to a halt, we need to calculate the torque required. Torque is the product of force and distance. In this case, the force acting on the balls is the weight of the balls, which can be calculated using the formula F = m * g, where m is the mass and g is the acceleration due to gravity. The distance is the length of the rod between the balls. Torque is given by the formula T = F * d, where T is the torque, F is the force, and d is the distance. So, the torque required to bring the balls to a halt can be calculated by finding the weight of the balls and multiplying it by the distance between them.

User Arijeet
by
5.0k points
4 votes

Answer: 0.235

Step-by-step explanation:

Given data.

M1 = 0.91 Kg

M2 = 2kg

L = 0.95m

N = 35rpm

t = 10.44secs

Solution:

• we first solve for the center of gravity

•we calculate our moment of inertia

• we calculate the angular velocity

• we solve for our torque ( t )

A 0.91 kg ball and a 2 kg ball are connected by a 0.95 m long rigid, massless rod-example-1
User Vicky P
by
4.9k points