Question

A chemist prepares a solution of silver(II) oxide by measuring out of silver(II) oxide into a volumetric flask and filling the flask to the mark with water. Calculate the concentration in of the chemist's silver(II) oxide solution. Round your answer to significant digits.

Answer 1

`M=7.3x10^(-9)(mol)/(L)`

Step-by-step explanation:

Hello!

In this case, since the values are not given in the question you asked, we are going to use a dataset found on ethernet for this problem, however, if you were given with different values you can follow the exact procedure with those you have.

In such a way, we consider 0.0011 μmol of silver oxide in a 150-mL volumetric flask until the mark, which means that the volume of the solution is 150 mL, in such way, since the molarity is defined by:

`M=(n_(solute))/(V_(solution))`

In units of mol/L we need to convert from μmol to mol as shown below:

`n=0.0011\mu mol*(1mol)/(1x10^6\mu mol) =1.1x10^(-9)mol`

Next the volume in liters is:

`V=150 mL*(1L)/(1000mL) =0.150L`

Thus, the concentration in mol/L turns out:

`M=(1.1x10^(-9)mol)/(0.150L)\\\\M=7.3x10^(-9)(mol)/(L)`

Best regards!