Question

A submarine left hawaii and travels east at an average speed of 10 mph. An aircraft. Carrier left at the same time and traveled in the opposite direction with an average speed of 20 mph. How long does the aircraft carrier need to travel before the ships are 300 mi. Apart?

Answer 1

10 hours

Explanation:

Given:

Average speed of submarine = 10 mph

Speed of carrier in the opposite direction = 20 mph

Distance between the submarine and carrier = 300 mi

To find:

The time taken so that the distance between them is 300 mi ?

Solution:

The relative speed when they are traveling in opposite direction = 10+20 = 30 mph

Formula:

`\text{Time }=\frac{\text{Distance Traveled}}{\text{Speed}}`

`\text{Time }= (300)/(30) = \bold{10\ hours}`

So, the answer is 10 hours.