Answer:
![Cu^(2+)S^(2-)(s)+2Ag^+N^(5+)O^(2-)_3(aq)\rightarrow Cu^(2+)(N^(5+)O^(2-)_3)_2(aq)+Ag^+_2S^(2-)(s)](https://img.qammunity.org/2021/formulas/chemistry/college/yfg2ck6v8ogstvvcg1a4s3rht6lydq8qd9.png)
It is a non-redox reaction.
Step-by-step explanation:
Hello.
In this case, when solid copper sulfate and aqueous silver nitrate react to form solid silver sulfide and aqueous solid silver sulfide we can write:
![CuS(s)+2AgNO_3(aq)\rightarrow Cu(NO_3)_2(aq)+Ag_2S(s)](https://img.qammunity.org/2021/formulas/chemistry/college/x4ijjan7w9kpuin16rfgy7hvol16bklryh.png)
In which the oxidation states are assigned based on the periodic table and taking into account that the left-handed ion is positively charged whereas the right-handed one is negatively charged:
![Cu^(2+)S^(2-)(s)+2Ag^+N^(5+)O^(2-)_3(aq)\rightarrow Cu^(2+)(N^(5+)O^(2-)_3)_2(aq)+Ag^+_2S^(2-)(s)](https://img.qammunity.org/2021/formulas/chemistry/college/yfg2ck6v8ogstvvcg1a4s3rht6lydq8qd9.png)
Thus, since the oxidation states do not change from reactants to products, we infer this is a non-redox reaction.
Best regards!