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Potatoes - Samples: Assume the weights of Farmer Carl's potatoes are normally distributed with a mean of 7.0 ounces and a standard deviation of 1.2 ounces. He bags his potatoes in groups of 6. You buy a bag and the total weight is 36 ounces. Here we determine how lucky or unlucky you are.

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Solution :

Given that : mean, μ = 7, standard deviation, σ = 1.2

Therefore, the mean potato weight in the bag of 6 is


$\bar{x} = (36)/(6)$

= 6 ounces.

Here we have μ = 7, σ = 1.2, n = 6

So, z-score for
$\bar{x} = 6 $ is


$z=\frac{\bar{x}-\mu}{\sigma/ \sqrt n}$

=
$(6-7)/(1.2/\sqrt6) = -2.04$

User Stanley Ulili
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