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MY NOTES ASK YOUR TEACHER In the Bohr model of the hydrogen atom, an electron in the 8th excited state moves at a speed of 3.42 104 m/s in a circular path of radius 3.39 10-9 m. What is the effective current associated with this orbiting electron

User Charito
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1 Answer

4 votes

Answer:

The value is
I = 2.568*10^(-7)\ A

Step-by-step explanation:

From the question we are told that

The speed of the electron is
v = 3.42*10^(4) \ m/s

The radius is
r = 3.39 *10^(-9) \ m

Generally the frequency of the electron is mathematically represented as


f = (v)/(2 \pi * r )

=>
f = (3.42 *10^(4))/(2 * 3.142 * 3.39*10^(-9) )

=>
f = 1.605 *10^(12) \ s^(-1)

Generally the current is mathematically represented as


I = e * f

Here e is the charge on an electron with value
e = 1.60*10^(-19) \ C

So


I = 1.60*10^(-19) *1.605 *10^(12)

=>
I = 2.568*10^(-7)\ A

User Surahman
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