Question

s adjusting the tension in each of two strings so that both vibrate at exactly 551 Hz. The tension in one of the strings is then increased slightly. As a result, six beats per second are heard when both strings vibrate. What is the new frequency of the string that was tightened

Answer 1

557 Hz

Step-by-step explanation:

The concepts needed to solve this question are the number of beats formed per second by two frequencies and the frequency of the vibrating string's vibrations.

Given that:

Actual frequency f= 551 Hz

Beat frequency Δf = 6

In as much as the tension is increased, its frequency will also increase

Thus; the new frequency of tightened string f' = f + Δf

f' = 551 Hz + 6 /s

f' = 551Hz + 6/s ( 1 Hz/s)

f' = 557 Hz