Question

A car travelling at 15 m/s comes to rest in a distance of 14 m when the brakes are applied.

Calculate the deceleration of the car.

Answer 1

-8.04 m/s2

Step-by-step explanation:

To find the answer to this, you have to use the 4th kinematic equation:

`v^(2) = v^(2)_(0) + 2ax`

You plug into the equation to get:

`0 = 15^(2) + 2a(14)`

solve for a to get

-8.04 m/s2