Answer:
The number
satisfies the conclusion of Rolle's Theorem for
.
Explanation:
According to the Rolle's Theorem, for all function continuous on
, there is a value
(
) such that:
(Eq. 1)
Where:
- First derivative of the function evaluated at
, dimensionless.
,
- Lower and upper bounds, dimensionless.
,
- Function evaluated at lower and upper bounds, dimensionless.
Let
, then upper and lower values are, respectively:
Lower bound (
)
![f(2) = 5-24\cdot (2) +4\cdot (2)^(2)](https://img.qammunity.org/2021/formulas/mathematics/college/revn29im5seuorqei1alwge216jxp2kkp0.png)
![f(2) = -27](https://img.qammunity.org/2021/formulas/mathematics/college/1tpcz9p8yqb3izxodaqdoco3d3nrit1n75.png)
Upper bound (
)
![f(4) = 5-24\cdot (4) +4\cdot (4)^(2)](https://img.qammunity.org/2021/formulas/mathematics/college/spxcyux39qmytjru1qc9705dbiztm5971l.png)
![f(4) = -27](https://img.qammunity.org/2021/formulas/mathematics/college/hjqk4bp9e4kq3u1a0sdyic99oen51ia4fz.png)
From Rolle's Theorem, we find that first derivative evaluated at
is:
![f'(c) = (-27-(-27))/(4-2)](https://img.qammunity.org/2021/formulas/mathematics/college/hc9ehya4ftddw1oebw1g6pshrz6vch9r5r.png)
![f'(c) = 0](https://img.qammunity.org/2021/formulas/mathematics/college/a0k2vweo9v8m1pjz24r696pvxdgn42obju.png)
Then, we find the first derivative of the function, equalize
to
and solve the resulting expression:
![f'(x) = -24+8\cdot x](https://img.qammunity.org/2021/formulas/mathematics/college/vzbwqxzjd4rkjkfwmnzcqk4cqekoub52mg.png)
![-24+8\cdot c = 0](https://img.qammunity.org/2021/formulas/mathematics/college/fh26hi5r6cztmk58mzqbuvf98czdi4k6vc.png)
![c = 3](https://img.qammunity.org/2021/formulas/mathematics/college/49pcqbbm32a706neioo1kvjw7m7w3dcpfp.png)
The number
satisfies the conclusion of Rolle's Theorem for
.