Question

Find the center and the radius of the circle x2 + y2 + 6x − 4y − 23 = 0.

Center: (−3, −2), radius: 6
Center: (−3, 2), radius: square root of six end square root
Center: (−3, 2), radius: 6
Center: (3, 2), radius: square root of six end square root

Answer 1

C

Explanation:

It can be written as,

(x+3)^2 +(y-2)^2-23-9-4=0

➡️ (x+3)^2 +(y-2)^2=36

➡️ (x+3)^2 +(y-2) ^2=6^2

Thus,

Centre =(-3,2)

Radius =6 units