Answer:
Explanation:
SHOW THAT:
sin³ 0 +cos³0 / sin 0+ cos 0 = 1 - sin 0 cos 0
Now, using the identity a^3 + b^3 = (a + b)(a^2 + b^2 - ab):
sin³ 0 +cos³0 = (sin 0 + cos 0)(sin² 0 +cos²0 - sin0 cos 0)
As sin² 0 +cos²0 = 1 we have:
sin³ 0 +cos³0 = ( sin 0 + cos 0)(1 - sin0 cos 0)
So we can write the left side of the original expression as
( sin 0 + cos 0)(1 - sin0 cos 0) / (sin 0+ cos 0)
= 1 - sin0 cos 0 = Right side
= and we are done!.