Question

A bowling ball weighing 25 N is dropped off the top of a 11 m tall building. What is the potential energy with respect to the ground when it has fallen half the height of the building?

a. 25 J b. 2.8 x 102 J c. 11 J d. 1.4 x 102 J

Answer 1

1.4x10²J

Step-by-step explanation:

Given parameters:

Weight of the bowling ball = 25N

Height of building = 11m

Unknown:

Potential energy when it has fallen half the height = ?

Solution:

Potential energy is the energy at rest in a body.

It is mathematically expressed as;

P.E = mgh

m is the mass

g is the acceleration due to gravity

h is the height

The height here is half of the building;

h =
`(11)/(2)`m

Now,

Weight = mg = 25N

So;

P.E = 25 x
`(11)/(2)` = 1.4x10²J