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HELP PLEASE!!
Finding the missing parts of a triangle.

HELP PLEASE!! Finding the missing parts of a triangle.-example-1

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Explanation:

Before we proceed, we must understand that we are dealing with a system of right angled triangles.

There are two types of right angle triangles';

45° - 45° - 90° 30° - 60° - 90°

In 45° - 45° - 90°, the adjacent is equal to the opposite

30° - 60° - 90°, there are three different sides

The longest side faces 90°, the shortest side will face the smallest angle and the intermediate will face 60°

A.

To find AB, use Pythagoras theorem;

AB² = AC² + BC²

AB² = 13² + 4²

AB² = 169 + 16 = 185

AB = √185 = 13.6

AB = 13.6

Angle A = 30°

Angle B = 60°

B.

AB² = BC² + AC²

The unknown is AC;

AC² = AB² - BC²

AC² = 5² - 4²

AC² = 9

AC = √9 = 3

Angle A = 60°

Angle B = 30°

C.

AB² = AC² + BC²

Insert the parameters and find AC;

AC² = AB² - BC²

AC² = 11² - 4.4²

AC² = 101.64

AC = √101.64

AC = 10.1

Angle A = 30°

Angle B = 60°

AC = 13

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