Question

How many grams of carbon dioxide are produced when 16.0

g of methane and 48.0 g of oxygen gas combust?
Molar mass of CH4 = 16.0 g/mol
Molar mass of O2 = 32.0 g/mol
Molar mass of CO2 = 44.0 g/mol

Answer 1

33.0

Step-by-step explanation:

for the people using ck12

Answer 2

Mass of CO₂ = 33 g

Further explanation

Complete combustion of Hydrocarbons with Oxygen will be obtained by CO₂ and H₂O compounds.

If O₂ is insufficient there will be incomplete combustion produced by CO and H and O

Reaction

CH₄ + 2O₂⇒CO₂ + 2H₂O

mol CH₄ :

`\tt =(16)/(16)=1`

mol O₂ :

`\tt =(48)/(32)=1.5`

A method that can be used to find limiting reactants is to divide the number of moles of known substances by their respective coefficients

`\tt CH_4:O_2=(1)/(1):(1.5)/(2)=1:0.75`

Because O₂ ratio smaller then O₂ becomes the limiting reactants

So mol CO₂ from limiting reactants

mol CO₂ :

`\tt (1)/(2)* 1.5=0.75`

mass CO₂ :

`\tt mass=mol* MW=0.75* 44=33~g`