Question

Consider the line y = x+5.

Ex+5.
Find the equation of the line that is parallel to this line and passes through the point (-9, -5).
Find the equation of the line that is perpendicular to this line and passes through the point (-9. – 5).

Plz help :)

Answer 1

parallel line equation: y=x+4

perpendicular line equation: y=-x-14

Explanation:

The initial slope is m=1.

Given for parallel line: m=1 ( for parallel line slope stays the same) x=-9 and y=-5

use the formula y=mx+b

-5=1(-9)+b

-5=-9+b

4=b

y=x+4

slope for perpendicular line is to flip the slope and change the sign.

m=-1, x=-9 and y=-5

-5=-1(-9)+b

-5=9+b

b=-14

y=-x-14