Question

7. A spring balance reads force in Newton. The scale is 20 cm long and reads from 0 to

60 N. Find the potential energy of the spring when it read 40 N. ​

Answer 1

The potential energy when it reads 40 N is
`PE = 5.33 \ J`

Step-by-step explanation:

From the question we are told that

The lowest reading of the spring balance is 0 N and this is at 0 cm = 0 m

The height reading of the spring balance is 60 N and this is at 20 cm = 0.20 m

Generally the length corresponding to the reading of 40 N is mathematically represented as

`d = (40 * 0.20 )/(60 )`

=>
`d = 0.133 \ m`

Generally the potential energy is mathematically represented as

`PE = m * g * d`

Here

`F = mg = 40 N`

So

`PE = 40 * 0.133`

=>
`PE = 5.33 \ J`