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Suppose sin a = 12/13 and sin b= 5/11. FInd cos(a+b)
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Suppose sin a = 12/13 and sin b= 5/11. FInd cos(a+b)

User Joseph Wambura
by
4.4k points

1 Answer

7 votes

Answer:

1.28 or 912/715

Explanation:

sine= opposite side/hypotenuse

cos=adjacent/ hypotenuse

sine a= 12/13 using the Pythagorean Theorem and solve for the missing side. (which is the adjacent side)

cos a = 5/13

Do the same for sine b

cos b= 9.8/11

add both the cosine value

(5/13)+(9.8/11)=1.28 or 912/715 in fraction form

User Robert J Berger
by
3.7k points
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