Answer:
the factors of f(x)=x^3+8x^2+5x-50 are (x-2)(x+5)(x+5)
Explanation:
We need to factorise the function
![f(x)=x^3+8x^2+5x-50](https://img.qammunity.org/2021/formulas/mathematics/college/vrbpi0soy5yipaf5tt9p5wgdgun8v44ys4.png)
If a number is a factor of this function than it must be completely divisible by last co-efficient. Our last co-efficient is -50
Checking few numbers:
![f(1)=(1)^(3)+8(1)^2+5(1)-50\\f(1)=1+8+5-50\\f(1)=-32\\Now \ putting \ x= 2 \\f(2)=(2)^(3)+8(2)^2+5(2)-50\\f(2)=8+8(4)+10-50\\f(2)=8+32+10-50\\f(2)=0](https://img.qammunity.org/2021/formulas/mathematics/college/pftrs56eijclxdqe2k9z3pbbyfgitstdxp.png)
So, f(2)=0 which means x-2 is a factor of the given function. Now we will perform long division of
by (x-2) to find other factors
The long division is shown in figure attached.
After long division we get:
![x^2+10x+25](https://img.qammunity.org/2021/formulas/mathematics/college/ozhslnx6qckjc85fpahsgxc4t2cicgbmdo.png)
The equation
can be further simplified as: (x+5)(x+5) or (x+5)^2
So, the factors of f(x)=x^3+8x^2+5x-50 are (x-2)(x+5)(x+5)