Question

One zero of the polynomial function f(x) = x3 − x2 − 12x is x = 0. What are the zeros of the polynomial function?

Answer 1

0, x = 4, and x = -3.

Explanation:

he zeros of the polynomial function f(x) = x3 − x2 − 12x are x = 0, x = 4, and x = -3. To find these, we can factor the polynomial and set each factor equal to zero. Since x = 0 is already given as a zero, we can factor out x from the polynomial to get f(x) = x(x^2 - x - 12) = x(x - 4)(x + 3) = 0. Thus, the other zeros are x = 4 and x = -3.

Answer 2

Explanation:

\Given :

x^{3} +x^{2} -20x

Solution:

x^{3} +x^{2} -20x

taking x common from the given polynomial

⇒x(x^{2} +x-20)=0

⇒x(x(x+5)-4(x+5))=0

⇒x(x+5)(x-4)=0

⇒ x=0 , x+5=0 , x-4=0

⇒x = 0 , x = -5 , x = 4