11,328 views
38 votes
38 votes
100pts Find mPQ in the circle to the right

100pts Find mPQ in the circle to the right-example-1
User Cvacca
by
2.5k points

2 Answers

19 votes
19 votes

We need indirectly m<POQ

See NR is a straight line so the three angles situated underneath are linear pair and supplementary

m<POQ

  • 180-(82+63)
  • 180-145
  • 35°
User Deepak S
by
3.3k points
21 votes
21 votes

Answer:

C) 35°

Explanation:

From inspection of the given diagram, it appears that the line segment NOR is the diameter of the circle (where point O is the center).

Angles on a straight line sum to 180°

⇒ ∠NOP + ∠POQ + ∠QOR = 180°

⇒ 82° + ∠POQ + 63° = 180°

⇒ ∠POQ = 180° - 82° - 63°

⇒ ∠POQ = 35°

As an arc measure equals its corresponding central angle measure:


\sf \implies \overset{\frown}{PQ}= \angle POQ


\sf \implies \overset{\frown}{PQ}=35^(\circ)

User Dragan Sekuloski
by
2.9k points