113k views
5 votes
State the vertex of f(x)=x^2-6x-40

1 Answer

3 votes

Note that f(x) = x² - 6x - 40 = 0 is the same as y = x² - 6x - 40.

To find the x of the vertex, we use the formula x = -b/2a.

So we have x = -(-6)/2(1) or x = 6/2 or x = 3.

To find the y of the vertex, we plug a 3 back in for x.

So we have y = (3)² - 6(3) - 40 or 9 - 18 - 40 which is -49.

So our vertex is the point (3,-49).

User Biziclop
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories