Question

The equation of a circle is x^2 + y^2 + 6y=7

Answer 1

x =
`-3 + √((4+x)(4-x))`

y =
`-3 - √((4+x)(4-x))`

Explanation:

`x^2 + y^2 + 6y=7\\`

⇒
`\left(x-a\right)^2+\left(y-b\right)^2`

`\left(x-0\right)^2+\left(y-\left(-3\right)\right)^2 =4^2`

What happened in this math problem:

• We used the standard circle formula to find the properties of the circle as well as its variables.