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The equation of a circle is x^2 + y^2 + 6y=7

User Krivvenz
by
8.1k points

1 Answer

4 votes

Answer:

x =
-3 + √((4+x)(4-x))

y =
-3 - √((4+x)(4-x))

Explanation:


x^2 + y^2 + 6y=7\\


\left(x-a\right)^2+\left(y-b\right)^2


\left(x-0\right)^2+\left(y-\left(-3\right)\right)^2 =4^2

What happened in this math problem:

  • We used the standard circle formula to find the properties of the circle as well as its variables.
User Vikash Kumar
by
8.4k points

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