1 Answer

Vikash Kumar · Answer 1 · 2023-10-08T13:53:11+0000

Answer:

x =
-3 + √((4+x)(4-x))

y =
-3 - √((4+x)(4-x))

Explanation:

$x^2 + y^2 + 6y=7\\$

⇒
$\left(x-a\right)^2+\left(y-b\right)^2$

$\left(x-0\right)^2+\left(y-\left(-3\right)\right)^2 =4^2$

What happened in this math problem:

We used the standard circle formula to find the properties of the circle as well as its variables.

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