Question

What is the acceleration of an object that is initially moving at 10.5 m/s and is moving at 13.5 m/s after 2 seconds

Answer 1

Answer:Hope it will help you.

Step-by-step explanation:

Answer 2

`\boxed {\boxed {\sf a= 1.5 \ m/s^2}}`

Step-by-step explanation:

Acceleration is the change in velocity over time, so it is calculated using the following formula.

`a= (v_f-v_i)/(t)`

The object is initially moving at 10.5 meters per second. After 2 seconds, it is moving at 13.5 meters per second.

• 
  `v_i`= 10.5 m/s
• 
  `v_f`=13.5 m/s
• t= 2 s

Substitute the values into the formula.

`a= (13.5 \ m/s - 10.5 \ m/s)/(2 \ s)`

Solve the numerator.

`a= (3 \ m/s)/(2 \ s)`

Divide.

`a=1.5 \ m/s/s \\a= 1.5 \ m/s^2`

The acceleration of the object is 1.5 meters per second squared.