Answer:
![\boxed {x = (5)/(4)}](https://img.qammunity.org/2021/formulas/mathematics/high-school/6r5hr6mqwuhogqg7aqrenbxc4fvtep6i57.png)
Explanation:
Solve for the value of
:
![(2)/(3)x + (1)/(6) = 1](https://img.qammunity.org/2021/formulas/mathematics/high-school/5bw6vbfzrdiejystz35yp0nyb4w7788d6e.png)
-Subtract
to both sides and convert the
into a fraction. Since they both fractions
and
both have the same denominators, then you would subtract the numerators:
![(2)/(3)x + (1)/(6) - (1)/(6) = 1 - (1)/(6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/qm8x95lmgg3jqux27yrtjgeutym6s7zbcv.png)
![(2)/(3)x = (6)/(6) - (1)/(6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/7pv91l4rswdksdvmkzpr46j5550exi4avr.png)
![(2)/(3)x = (5)/(6)](https://img.qammunity.org/2021/formulas/mathematics/high-school/vk04f6m0bvwcjv5stl05f3poq9badl3z6b.png)
-Multiply both sides by
which is the reciprocal of
. By multiplying two you need to multiply both numerators and denominators:
![x = (5)/(6) * ((2)/(3))](https://img.qammunity.org/2021/formulas/mathematics/high-school/sv753jse6bx670ra9gx0wh55b9dwhx2949.png)
![x = (5 * 3)/(6 * 2)](https://img.qammunity.org/2021/formulas/mathematics/high-school/hadrit5ubb8s91jc38n4ytum3df7fxiz6l.png)
![x = (15)/(12)](https://img.qammunity.org/2021/formulas/mathematics/high-school/d8z03gwdjijbq71xgp9dlcn2bqnjja5r9m.png)
-Simplify the fraction by reducing by
:
![x = (15)/(12)](https://img.qammunity.org/2021/formulas/mathematics/high-school/d8z03gwdjijbq71xgp9dlcn2bqnjja5r9m.png)
![\boxed {x = (5)/(4)}](https://img.qammunity.org/2021/formulas/mathematics/high-school/6r5hr6mqwuhogqg7aqrenbxc4fvtep6i57.png)
Therefore, the value of
is
.