Question

(3x - 16) = (6x + 7) = (11y - 32)

Answer 1

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`3x - 16 = 6x + 7`

`6x + 7 = 3x - 16`

Subtract sides 7

`6x + 7 - 7 = 3x - 16 - 7`

Simplification

`6x = 3x - 23`

Subtract sides 3x

`- 3x + 6x = - 3x + 3x - 23`

Simplification

`3x = - 23`

Divide sides by 3

`(3)/(3) x = - (23)/(3) \\`

Simplification

`x = - (23)/(3) \\`

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`6x + 7 = 11y - 32`

Put the value of x

`6( - (23)/(3) ) + 7 = 11y - 32 \\`

`2( - 23) + 7 = 11y - 32`

`- 46 + 7 = 11y - 32`

`- 39 = 11y - 32`

`11y - 32 = - 39`

Add sides 32

`11y - 32 + 32 = - 39 + 32`

`11y = - 7`

Divide sides by 11

`(11)/(11) y = - (7)/(11) \\`

Simplification

`y = - (7)/(11) \\`

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