Answer:
Number of terms = 31.
Explanation:
Sum of n terms of an A S with first term 1 and common difference 1:-
496 = (n/2)(2(1) + 1(n - 1))
496 = (n/2)(n + 1)
n^2/2 + n/2 = 496 Multiply through by 2:-
n^2 + n = 992
n^2 + n - 992 = 0
(n - 31)(n + 32) = 0
n = 31 (we ignore the negative).