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State the domain and range of: y = arcsin (x²)​

User Eplawless
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1 Answer

6 votes

Answer:

Domain is -1 ≤ x ≤ 1.

Range is 0 ≤ y ≤ π/2.

Explanation:

The arcsin only exists for -1 ≤ x ≤ 1 so this domain is

-1 ≤ x ≤ 1.

When x = 1 or -1 , y = arcsin(1^2) = π/2

When x = 0 , y = 0.

User Yonisha
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