Question

Please help with 5.a and 5.B :/

Answer 1

Explanation:

#5a

The format
`y = P(1+r)^x` is where

P refers to the initial amount, in this case $2.28

r = the rate (in decimal), in this case, (0.03)

so
`y = 2.28(1+0.03)^x\\y = 2.28(1.03)^x\\`

#5b

Now, we just have plug 20 into x

`y = 2.28(1.03)^2^0 = 4.117933615 = 4.18`