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A baseball dropped from the roof of a 47 meter building. How long would an object take to free-fall of the top of the building? [Neglect friction.]

4.8 s
4.8 s

2.1 s
2.1 s

9.6 s
9.6 s

3.1 s

User Turid
by
5.6k points

1 Answer

3 votes

Answer:

t = 3.1 seconds

Step-by-step explanation:

Given that,

A baseball dropped from the roof of a 47 meter building.

Let t is the time taken by the baseball to free-fall of the top of the building. It can be calculated using second equation of motion as follows :


s=ut+(1)/(2)at^2

Here, u = 0 and a = g


s=(1)/(2)gt^2\\\\t=\sqrt{(2s)/(g)} \\\\t=\sqrt{(2* 47)/(9.8)} \\\\t=3.09\ s

or

t = 3.1 s

So, it will take 3.1 seconds to free-fall of the top of the building.

User Nathan Colgate
by
5.9k points