Question

What is the total number of joules of heat needed to change 300 g of water to

steam at 100 degrees C?*

Answer 1

6.78 × 10⁵ J

Step-by-step explanation:

Step 1: Given and required data

• Mass of water (m): 300 g

• Latent heat of vaporization of water (ΔH°vap): 2260 J/g

Step 2: Calculate the heat (Q) required to vaporize 300 grams of water

We will use the following expression.

Q = ΔH°vap × m

Q = 2260 J/g × 300 g

Q = 6.78 × 10⁵ J

6.78 × 10⁵ Joule will be required to convert 300 g of water to steam at 100 °C.