Answer:
Explanation:
We can set up a system of equations
There are 17 animals:
I will use C for chickens, M for cows
![C + M = 17](https://img.qammunity.org/2021/formulas/mathematics/high-school/zwjeppu6v6uhq6peg4992k2rtf6nnhao3z.png)
There are 50 legs in total. Chickens have two legs, cows have 4 legs, so
![2C + 4M = 50](https://img.qammunity.org/2021/formulas/mathematics/high-school/uf4uz8bavwk9bq0t2k4opmyyym4cbfl3d7.png)
We can solve for either C or M in the top equation and substitute it below. Either choice works.
![C = 17 - M\\2(17-M) + 4M = 50\\34 - 2M + 4M = 50\\2M = 16\\M = 8\\\\M = 17-C\\2C + 4(17-C) = 50\\2C + 68 - 4C = 50\\-2C = -18\\C = 9](https://img.qammunity.org/2021/formulas/mathematics/high-school/a9x0jyogmefj2kejc5w3k9u8sx9ejrlaub.png)
There are 9 Chickens and 8 Cows.