Answer:
1 + i and 2 + 3i
Explanation:
Formula:
(c + d i)(e + f i) = (c e - d f) + (c f + d e) i
……………………………………………………………
if c, d, e, and f are positive real numbers
then
c f + d e is a positive number.
then
The product of the two complex numbers
lies in Quadrant 1 or Quadrant 2.
Since , c, d, e, and f are positive real numbers
Then
The two complex numbers c + d i and e + f i lie in Quadrant 1
We want to find an example of two complex numbers
That lie in Quadrant 1 ,such that ,their product lies in the other possible
Quadrant, which is Quadrant 2.
EXAMPLE:
Let c + d i = 1 + i
e + f i = 2 + 3i
By applying the formula:
(c + d i)(e + f i) = (c e - d f) + (c f + d e) i
We get :
(1 + i)(2 + 3i) = -1 + 5i