Question

PLEASE HELP ME I DONT UNDERSTAND THIS AND THIS IS TIMED

In an experiment, a rubber stopper is attached to one end of a string. The stopper is whirled in a horizontal circular path of a diameter of 1.0 meter at a constant speed. The stopper completes one revolution in 0.2 seconds. Approximately what is the magnitude of the stoppers speed?

A) 3.1 m/s
B) 6.3 m/s
C) 16 m/s
D) 31 m/s

Answer 1

The magnitude of the stopper's speed can be determined using the formula for tangential speed, which is 2πr / T. Substituting the given values, the magnitude of the stopper's speed is approximately 3.1 m/s.

Step-by-step explanation:

The magnitude of the stopper's speed can be determined by calculating the tangential speed. The tangential speed is given by the formula:

Tangential speed = 2πr / T

Where r is the radius and T is the period (time taken for one revolution). Substituting the given values:

Tangential speed = 2π * (0.5) / 0.2 = 3.14 m/s

Therefore, the magnitude of the stopper's speed is approximately 3.1 m/s.

Answer 2

(C)

Step-by-step explanation:

The circle has a radius r = 0.5 m, which means that its circumference C is

`C = 2\pi r = 2\pi(0.5\:\text{m}) = 3.14\:\text{m}`

One revolution means that the stopper travels a distance equal to the circumference of the circle so the velocity of the stopper is

`v = (C)/(t) =\frac{3.14\:\text{m}}{0.2\:\text{s}} = 15.7\:\text{m/s} \approx 16\:\text{m/s}`