Question

PLEASE PLEASE PLEASE PLEASE HELP ME WITH THISSSSS

Answer 1

In ∆DAC and ∆BCA

Diagonals of a parallelogram bisect each other

• AE=EC
• DE=EB

Opposite angles are equal

• <ABC=<ADC

Also

• AE is common side

And

Opposite sides are equal in a parallelogram

• AD=BC

So by Side-angle-side similarity

Both triangles are equal

Hence

• <DAC=<BCA(Proved)