Question

A 3.00 kg object is moving at 5.00 m/s EAST. It catches up to and strikes a 6.00 kg that is moving EAST at 2.00 m/s. The objects undergo an elastic collision in the EAST-WEST direction. The velocity of the 3.00 kg object after the collision is

Answer 1

The correct solution will be "1 m/s". The further explanation is given below.

Step-by-step explanation:

The given values are:

m₁ = 3.00 kg

m₂ = 6.00 kg

v₁i = 5.00 m/s

v₂i = 2.00 m/s

Now,

⇒
`v_1f = (((m_(1)-m_2)/(m_1+m_2) ) v1i )/(((2m_2)/(m_1+m_2) ) v_2i)`

On substituting the values, we get

⇒
`=((3-6)/(3+6) )* 5 + ((2* 6)/(3+6) )* 2`

⇒
`= 1 \ m/s`