Question

SEBUAH ALAT PEMANAS AIR 200 WATT, 220 VOLT YANG DI PASANG PADA SUMBER TEGANGAN 110 VOLT, MENYERAP DAYA LISTRIK​

Answer 1

50 Watt

Step-by-step explanation:

The question says "A water heater 200 Watt, 220 volts which is installed on a voltage source of 110 volts, absorbs electric power of ?"

The formula for electric power is given by :

`P=(V^2)/(R)`

V is voltage and R is resistance

The value of R is same for both the cases.

`R=(V^2)/(P)`

or

`(V_1^2)/(P_1)=(V_2^2)/(P_2)`

We have, P₁ = 200 W, V₁ = 220 V, V₂ = 110 V, P₂ = ?

`(V_1^2)/(P_1)=(V_2^2)/(P_2)\\\\P_2=(P_1V_2^2)/(V_1^2)\\\\P_2=(200* 110^2)/(220^2)\\\\P_2=50\ W`

So, the required power is 50 Watt.