Question

An AAbb strain is crossed to an aaBB strain and the resulting progeny self-crossed. If A andB are located 10 cM apart from each other on the same chromosome, what percentage of the self-progeny will be of genotype aaBB

Answer 1

20.3%

Step-by-step explanation:

Given that:

An AAbb strain is crossed to an aaBB strain

i.e.

AAbb × aaBB

gametes Ab aB

For F₁

generation;

If the resulting progeny are now self-crossed.

We know that the genetic distance between these two genes on the same chromosome is said to be 10 cM.

i.e. the recombinant gene = 10%; Hence, the parental gene will be (100 - 10)% = 90%

Ab × aB = Aa AB ab Bb

From above; the parental gene;

Ab and aB = 90% with each being 45%

i.e. Ab = 45% and aB = 45%

while the recombinants genes are:

AB and ab = 10%

i.e. AB = 5% and ab = 5%

Finally; the percentage of aaBB is = aB% × aB% × 100%

the percentage of aaBB is = 0.45 × 0.45 × 100%

the percentage of aaBB is = 20.25% ≅ 20.3%