Question

g To see why an MRI utilizes iron to increase the magnetic field created by a coil, calculate the current needed in a 400 loop-per-meter circular coil 0.660 m in radius to create a 1.20 T field (typical of an MRI instrument) at its center with no iron insert.

Answer 1

The current inside the MRI solenoid is 2387 A.

Step-by-step explanation:

Given;

number of turns, N = 400

radius of the loop, r = 0.66 m

magnetic field, B = 1.2 T

The magnetic field strength inside MRI Solenoid is given by;

B = Nμ₀I

Where;

I is the current needed in the loop

`B= N\mu_o I\\\\I = (B)/(N \mu_o) \\\\I = (1.2)/((400)(4\pi* 10 ^(-7))) \\\\I = 2387 \ A`

Therefore, the current inside the MRI solenoid is 2387 A.