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How would you convert 500cc of 2M H2so4 in g/l and normality?​

1 Answer

2 votes

Concentration :

196 g/L and 4 N

Further explanation

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight / volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

500 cc of 2M H₂SO₄

V = 500 cc = 0.5 L

mol H₂SO₄


\tt mol=M* V=2* 0.5=1

mass H₂SO₄ (MW = 98 g/mol)


\tt mass=mol* MW=1* 98=98~g

concentration in g/L :


\tt (98)/(0.5)=196~g/L

concentration in normality

Relationship between normality and molarity

N = M x n (n=valence , amount of H⁺ or OH⁻)

so :


\tt N=2* 2(n=2~for~H_2SO_4\rightarrow 2H^+)\\\\N=4

User Kenneth Baltrinic
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