Answer:
The five arithmetic means between 14 and 86 are 26,38,50,62,74
Explanation:
We need to find five arithmetic means between 14 and 86
The formula used to find arithmetic mean is:
![a_(n)=a_(1) +(n-1)d](https://img.qammunity.org/2021/formulas/mathematics/college/4akmscvz60v8nk0b80cpdgy4fhrgmle4uc.png)
Where n is the number of terms and d is the common difference
We are given 1st and 7th term.
Using 7th term to find value of d
![a_(n)=a_(1) +(n-1)d\\a_(7)=14 +(7-1)d\\86=14+6d\\86-14=6d\\72=6d\\d=(72)/(6)\\d=12](https://img.qammunity.org/2021/formulas/mathematics/college/lwmxam4528gti7zw50fa3hwfc9z4q212dt.png)
So, difference between each term d is 12
Now finding five arithmetic terms i.e a₂, a₃, a₄, a₅, a₆
Using the formula
to find terms
Finding term a₂
![a_(n)=a_(1) +(n-1)d\\a_(2)=14 +(2-1)12\\a_(2)=14 +12\\a_(2)=26](https://img.qammunity.org/2021/formulas/mathematics/college/vos3gk3sk8e84d7i9zm7rw58vs8pihs6r9.png)
Finding term a₃
![a_(n)=a_(1) +(n-1)d\\a_(3)=14 +(3-1)12\\a_(3)=14 +2*12\\a_(3)=38](https://img.qammunity.org/2021/formulas/mathematics/college/vpbodsl7xtta0gsdz4rhvb710ngy7hzm4j.png)
Finding term a₄
![a_(n)=a_(1) +(n-1)d\\a_(4)=14 +(4-1)12\\a_(4)=14 +3*12\\a_(4)=50](https://img.qammunity.org/2021/formulas/mathematics/college/s9ay5kpkbrgqw3d4vm07r2t7dhf1q14ewk.png)
Finding term a₅
![a_(n)=a_(1) +(n-1)d\\a_(5)=14 +(5-1)12\\a_(5)=14 +4*12\\a_(5)=62](https://img.qammunity.org/2021/formulas/mathematics/college/ftv5e8cr4c4cuswlpxfeojgna1i7q5qeep.png)
Finding term a₆
![a_(n)=a_(1) +(n-1)d\\a_(6)=14 +(6-1)12\\a_(6)=14 +5*12\\a_(6)=74](https://img.qammunity.org/2021/formulas/mathematics/college/arf25zxfa3msp6ijvvbjjw244l7kdxrqrj.png)
So, the five arithmetic means between 14 and 86 are 26,38,50,62,74