108k views
4 votes
Find an equation with a solution of

x
=
5
of multiplicity
1
, and a solution of
x
=

3
of multiplicity
2
.

User MaNDOOoo
by
6.0k points

2 Answers

3 votes
Please someone answer this
User Stillinbeta
by
5.9k points
2 votes

Answer: (x+5)(x-3)2 = 0

Step-by-step explanation: To write this equation as a polynomial, you must multiply it out.

begin by squaring the binomial, and remember to express this as a trinomial (middle term will be -6x).

Then, to finish the job, multiply that trinomial by the factor x+5. Hope this will help you.

User Garvey
by
6.4k points