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What is the value of d/dx (6/x^4 + 1/x^2) at x = -1 ?
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What is the value of d/dx (6/x^4 + 1/x^2) at x = -1 ?

What is the value of d/dx (6/x^4 + 1/x^2) at x = -1 ?-example-1
User Benesch
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1 Answer

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Answer:

\frac{d}{dx}\left(\frac{1+x^4+x^6}{x^2+x+1}\right)=\frac{4x^7+5x^6+8x^5+3x^4+4x^3-2x-1}{\left(x^2+x+1\right)^2}

Explanation:

User Safi Nettah
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