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1 vote
What is the equation of the line that passes through the point
(5,-2) and has a slope of 6/5

1 Answer

4 votes

Answer:

y =
(6x)/(5) - 8

Explanation:

given slope m =
(6)/(5)

point (5, -2) for (x1, y1)

equation for point slope form

y - y1 = m(x- x1)

y - (-2) =
(6)/(5) (x -5)

y + 2 =
(6)/(5)x - 6, simplify

y =
(6x)/(5) - 8,

further you can multiply by 5 to get rid of fraction

5y = 6x - 40

User Rudra
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