Question

What is the equation of the line that passes through the point
(5,-2) and has a slope of 6/5

Answer 1

y =
`(6x)/(5)` - 8

Explanation:

given slope m =
`(6)/(5)`

point (5, -2) for (x1, y1)

equation for point slope form

y - y1 = m(x- x1)

y - (-2) =
`(6)/(5)` (x -5)

y + 2 =
`(6)/(5)`x - 6, simplify

y =
`(6x)/(5)` - 8,

further you can multiply by 5 to get rid of fraction

5y = 6x - 40