Answer:
[2, ∞)
Explanation:
None of the expressions will yield a number less than 2 using the domain of xs stated.
3, x<0
All numbers less than 0 would lead to the range being 3
![x^(2) +2, 0\leq x<2](https://img.qammunity.org/2021/formulas/mathematics/high-school/c9x8u6cix44hgygprog7dtib0u3n1mjerz.png)
If we use 0, range= 2 (because (0)^2+2=2) and x=1 would yield range = 3
![(1)/(2) x+5, x\geq 2](https://img.qammunity.org/2021/formulas/mathematics/high-school/kdsih3lvgqgejwpkvhtrorefjkmeken74r.png)
Using 2 for x, we get range=6 and the numbers keep going till infinity