Question

A farmer had 888888 melons growing in her garden. In June, the farmer had picked 141414 melons. In July, a thunderstorm knocked a branch from a tree and crushed half the melons that remained in the garden. Then the farmer picked the rest.

How many melons did the farmer pick in June and July combined?

Answer 1

515151 melons were picked in June and July combined.

Explanation:

Converted to an equation:

let p = melons picked in June and July combined

`p = 141414 + ((888888 - 141414))/(2)`

The first part
`+ 141414` represents the melons that were picked in June.

The second part
`((888888 - 141414))/(2)` represents the melons picked in July, which is the original amount of melons, mines those picked in June, halved.

Now we can solve the equation.

`p = 141414 + (747474)/(2)`

`p = 141414 + 373737`

`p = 515151`

∴ There were 515151 melons picked in June and July combined.