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Cscx=cscx+secx/1+tanx

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4 votes

Answer:


\csc \left(x\right)=(\csc \left(x\right)+\sec \left(x\right))/(1+\tan \left(x\right))


=(1)/(\sin \left(x\right)) (expressed with sine and cosine)


(1)/(\sin \left(x\right))=\csc \left(x\right)


=\csc \left(x\right)

Therefore, the identity has been proven true.

User Heilerich
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