Answer:
-98
Explanation:
Given:
2+4+6 +⋯ +48−3−5−7 − … −51
Find solution:
(2+4+6 +⋯ +48)−(3+5+7+ …+51)
Computation:
an = a + (n-1)d
For
(2+4+6 +⋯ +48)
48 = 2 + (n-1)2
n=22
For
(3+5+7+ …+51)
51 = 3 + (N-1)2
N = 24
Sn = n/2(a+an)
So
22/2(2+48)-24/2(3+51)
550 - 648
-98