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Mr. Mole left his burrow that lies 7 meters below the ground and started digging his way deeper into the

ground, descending at a constant rate. After 6 minutes, he was 16 meters below the ground.

1 Answer

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Answer:

A(t)=-1.5t-7

Step-by-step explanation:

It is given that Mr. Mole left his burrow that lies 7 meters below the ground and after 6 minutes, he was 16 meters below the ground.

It means the line passing thought the points (0,-7) and (6,-16). It means the initial value is -7.

He started digging his way deeper into the ground, descending at a constant rate. The rate of change is

The rate of change is -1.5.

A(t) denote Mr. Mole's altitude relative to the ground A (measured in meters) as a function of time t (measured in minutes).

Therefore the function's formula is , here negative sign shows the Mr. Mole's altitude relative to below the ground A

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