Question

Three 20.0 ohm resistors are

connected in parallel and attached to
a 5.00 V battery. How much current
flows out of the battery?

Answer 1

0. 75A

Step-by-step explanation:

R1=20omh

R2=20omh

R3=20omh

equivalent voltage (V)= 5.00V

equivalent resistance (R) = ?

equivalent current (I)= ?

since, they are in parallel so,

1/R = 1/R1 + 1/R2 + 1/R3

1/R = 1/20 + 1/20 + 1/20

1/R = 3/20

R = 6.67 ohm

Now,

from ohm's law

V= IR

or, 5 = 6.67*I

or, I = 0.749

hence, I= 0.75A