Question

In a field, dry fodder for the cattle is heaped in a

conical shape. The height of the cone is 2.1 m and
diameter of base is 7.2 m. Find the volume of the
fodder. If it is to be covered by polythene in the
rainy season, then how much minimum polythene
22
sheet is needed ? (π and 17.37 = 4.17)
7
T =​

Answer 1

volume of fodder=1/3pie R^2h=
`(1)/(3) *(22)/(7) * (3.6)^2 *2.1=28.51m^3`

l^2=r^2+h^2

l^2=(2.1)^2+(3.6)^2

l^2=4.441+12.96=17.37

l=
`√(17.37)`=4.17m

minimum area of polythene to cover fodder=pieRl=
`(22)/(7) *3.6*4.17=47.18m^2`

the volume of fodder is
`28.51m^3` and minimum area of polythene to cover fodder in the rainy seasonv47.18m^3